To determine the power of the device needed to solve this problem, we can use the formula for calculating the power of a lens:
\[ P = \frac{1}{f} \]
where \( P \) is the power of the lens in diopters and \( f \) is the focal length of the lens in meters. In this case, since the students cannot see objects closer than 1m from their eyes, we need a lens that can help them focus on objects closer than 1m.
To calculate the power of the required lens, we first need to determine the focal length of the lens. Since the students can't focus on objects closer than 1m, the focal length of the lens will be the distance at which the objects become clear, which is 1m. Therefore, we have:
\[ f = 1m = 1 \, \text{m} \]
Now, we can substitute the focal length into the formula for lens power:
\[ P = \frac{1}{1} = 1 \, \text{diopter} \]
So, the power of the lens needed to help the students focus on objects closer than 1m is 1 diopter.
students complain that they can not see object closer than 1m from their eyes. determine the power of device used to solve this problen
1 answer
1 answer