To show that the expressions \((x-5)(x+3)\) and \(2x^2 - x^2 - 2x - 20 + 5\) are equivalent, we will use the Distributive Property to expand Expression 1 and simplify Expression 2.
Step 1: Expand Expression 1
\[ (x-5)(x+3) = x \cdot x + x \cdot 3 - 5 \cdot x - 5 \cdot 3 \] \[ = x^2 + 3x - 5x - 15 \] \[ = x^2 - 2x - 15 \]
Step 2: Simplify Expression 2
Now, let's simplify Expression 2: \[ 2x^2 - x^2 - 2x - 20 + 5 \] Combine like terms: \[ = (2x^2 - x^2) - 2x - 20 + 5 \] \[ = x^2 - 2x - 15 \]
Conclusion
After performing the calculations, we find that both expressions simplify to \(x^2 - 2x - 15\). Thus, we can conclude that the two expressions are equivalent.
Answer: Expression 1 simplifies to \(x^2 - 2x - 15\) and Expression 2 simplifies to \(x^2 - 2x - 15\), proving they are equivalent; both expressions ultimately equal \(x^2 - 2x - 15\).