Structures of Expressions Unit Test

15 of 1715 of 17 Items

Question
Use the Distributive Property to prove that these algebraic expressions are equivalent. Explain your answer in one sentence for each expression and show your work.

Expression 1: (x−5)(x+3)


Expression 2: 2x2−x2−2x−20+5


(4 points)

1 answer

To show that the expressions \((x-5)(x+3)\) and \(2x^2 - x^2 - 2x - 20 + 5\) are equivalent, we will use the Distributive Property to expand Expression 1 and simplify Expression 2.

Step 1: Expand Expression 1

\[ (x-5)(x+3) = x \cdot x + x \cdot 3 - 5 \cdot x - 5 \cdot 3 \] \[ = x^2 + 3x - 5x - 15 \] \[ = x^2 - 2x - 15 \]

Step 2: Simplify Expression 2

Now, let's simplify Expression 2: \[ 2x^2 - x^2 - 2x - 20 + 5 \] Combine like terms: \[ = (2x^2 - x^2) - 2x - 20 + 5 \] \[ = x^2 - 2x - 15 \]

Conclusion

After performing the calculations, we find that both expressions simplify to \(x^2 - 2x - 15\). Thus, we can conclude that the two expressions are equivalent.

Answer: Expression 1 simplifies to \(x^2 - 2x - 15\) and Expression 2 simplifies to \(x^2 - 2x - 15\), proving they are equivalent; both expressions ultimately equal \(x^2 - 2x - 15\).

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