Stomach acid is composed primarily of HCl. If the concentration of the acid is 0.010M and it has a volume of 70 mL, how many generic tablets would you need to fully neutralize the acid? (Use your data)

Question

I just don't know where to start for this question, or the steps to answer it.

Answer 1

depends on tablet size, and the contents. Dosages are available from 500mg to 1175 mg.

So we will start with the "extra Strength" 750 mg, CaCO3

moles acid: .01*.070=.007 moles

Now it takes half that number of moles of calcium carbonate ..

.0035=.750*N*/molmassCaCO3

N= .0035*mllemassCaCO3/.750

N= .0035*100/.750 = .46 tabs

Answer 2

Wait, could you please explain a little more in depth please? I got lost after you started with the Extra Strength.

The generic brand I'm using has 500 mg of active ingredient (CaCO3).

Also, can you explain why you took half the number of moles of CaCO3??