Steve McSpoke left home on his bicycle at 8am, traveling at 18km/h. At 10am, Steve's brother set out after him on a motorcycle, following the same route. The motorcycle traveled at 54km/h. How long had steve traveled when his brother overtook him?

Answer 1

Steve's brother time to catch-up --- t hrs
Steve's time to catch-up by brother -- t+2

54t = 18(t+2)
54t = 18t + 36
36t = 36
t = 1

Steve had biked for 3 hours, when his brother overtook him.

Answer 2

thanks

Answer 3

Also, how far had steve traveled when his brother overtook him?

Answer 4

simply sub in the value of t = 1 into both distances., you will obviously get the same answer since they both went the same distance.

Answer 5

Reiny, how can you show me how to do the last part wirten out?

Thank you so much!

Answer 6

neverminds. I got it.