Steve how does √((1.342t^2)^2 + (6.040t)^2) = 12.0

Question

t = 1.839
I don't get it can you explain further?
I took the square root of (1.342t^2)^2+(6.040t)^2 and it gives me 6.19

Answer 1

1.34^2 t^4 + 6.04^2 t^2
if t = 1.839
t^2 = 3.382
t^4 = 11.437

20.536 + 123.381

143.9
sqrt of that = 12 close enouggh