Let distance be D km, and
the current be C km/h
His speed is 8 km/h in still water.
So his speed upstream is
D/3.25=8-C
and downstream,
D/1.5=8+C
Cross multiply each to get
D = 3.25(8-C)
D=1.5(8+C)
Solve by comparison
1.5(8+C)=3.25(8-C)
Isolate C
4.75C = 8(3.25-1.5)
C=8*1.75/4.75
= 2.9 km/hr approximately
Check that the solution works by substituting the solution into the original equations.
Steve can kayak at 8 km/h in still water. On the river, Steve and the kayak travel slower upstream due to the current. It takes him 1.5 h for a trip downstream, but
3.25 h for the same distance upstream. Determine the speed of the river’s current.
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