Answer:
Potassium chloride (KCl) has a molecular weight of 74.55 g/mol.
Therefore, the amount of potassium chloride in the container is:
20 mL x 5 mEq/mL x 74.55 g/mol = 745.5 g
Sterile solutions of potassium chloride (KCl) containing 5 mEq/mL are available
in 20-mL containers. Calculate the amount, in grams, of potassium chloride in
the container.
1 answer