Stephanie wants to paint the door to her shed purple. How much paint will cover the door if it is 60 3/8 inches high, 36 3/5 inches long, and 2.2 inches wide? Round the answer to the nearest tenth.(1 point) Responses 4,827 square inches 4,827 square inches 4,665.7 square inches 4,665.7 square inches 4,826 3/4 square inches 4,826 Start Fraction 3 over 4 End Fraction square inches 4,846.1 square inches

1 answer

To find the surface area of the door, we need to calculate the area of each of the four sides.

1. For the front side (60 3/8 inches high and 36 3/5 inches long):
Area = Height x Length
Area = (60 3/8) x (36 3/5)
Area ≈ 60.375 x 36.6
Area ≈ 2207.35 square inches

2. For the back side (60 3/8 inches high and 36 3/5 inches long) - same as front side:
Area ≈ 2207.35 square inches

3. For the two side panels (60 3/8 inches high and 2.2 inches wide):
Area = Height x Width
Area = 60.375 x 2.2
Area ≈ 132.825 square inches
Since there are two side panels, the total area for the side panels is 2 x 132.825 = 265.65 square inches

Now, to find the total surface area of the door, we sum up the areas of each side:
Total area = 2207.35 + 2207.35 + 265.65
Total area ≈ 4680.35 square inches

Rounded to the nearest tenth, the total paint needed to cover the door is approximately 4,665.7 square inches.

Therefore, the answer is:
4,665.7 square inches