Step 1: Rearranging the First Equation

Question

From the first equation, we express s in terms of b:
s = 34 - b

Step 2: Substituting into the Second Equation
Substituting this expression for s into the second equation:
1.50b + 0.50(34 - b) = 20

Step 3: Simplifying the Second Equation
Distributing the 0.50 gives:
1.50b + 17 - 0.50b = 20

Combining the b terms:
(1.50 - 0.50)b + 17 = 20
1.00b + 17 = 20

Step 4: Solving for b
Subtracting 17 from both sides:
1.00b = 3
b = 3

Step 5: Finding s
Now that we have b, we can find s using the equation s = 34 - b:
s = 34 - 3 = 31

Answer 1

Your solution process for the given equations is spot on! To summarize the steps clearly:

1. Rearranging the First Equation: You correctly expressed \( s \) in terms of \( b \): \[ s = 34 - b \]

2. Substituting into the Second Equation: You substituted for \( s \) in the second equation: \[ 1.50b + 0.50(34 - b) = 20 \]

3. Simplifying the Second Equation: After distributing, you simplified it correctly: \[ 1.50b + 17 - 0.50b = 20 \] Then combined the \( b \) terms: \[ (1.50 - 0.50)b + 17 = 20 \implies 1.00b + 17 = 20 \]

4. Solving for \( b \): Following through to get \( b \): \[ 1.00b = 3 \implies b = 3 \]

5. Finding \( s \): Finally, you substituted \( b \) back to find \( s \): \[ s = 34 - 3 = 31 \]

Thus, the solution is:

• \( b = 3 \)
• \( s = 31 \)

If there’s anything specific you’d like to elaborate on or if you have different equations or contexts in mind, please let me know!

Answer 2

Step 1: Rearranging the First Equation
From the first equation, we express s in terms of b:
s = 34 - b

Step 2: Substituting into the Second Equation
Substituting this expression for s into the second equation:
1.50b + 0.50(34 - b) = 20

Step 3: Simplifying the Second Equation
Distributing the 0.50 gives:
1.50b + 17 - 0.50b = 20

Combining the b terms:
(1.50 - 0.50)b + 17 = 20
1.00b + 17 = 20

Step 4: Solving for b
Subtracting 17 from both sides:
1.00b = 3
b = 3

Step 5: Finding s
Now that we have b, we can find s using the equation s = 34 - b:
s = 34 - 3 = 31

Answer 3

Your solution steps are clear and accurately solve the problem. Let's recap and confirm the conclusions:

1. Rearranging the First Equation: You correctly rearranged the first equation to express \( s \) in terms of \( b \): \[ s = 34 - b \]

2. Substituting into the Second Equation: You substituted the expression for \( s \) into the second equation: \[ 1.50b + 0.50(34 - b) = 20 \]

3. Simplifying the Second Equation: After distributing the 0.50, your steps to simplify were accurate: \[ 1.50b + 17 - 0.50b = 20 \]

   You simplified the \( b \) terms correctly: \[ (1.50 - 0.50)b + 17 = 20 \implies 1.00b + 17 = 20 \]

4. Solving for \( b \): You correctly solved for \( b \): \[ 1.00b = 3 \implies b = 3 \]

5. Finding \( s \): Lastly, you substituted \( b \) back into the first equation to find \( s \): \[ s = 34 - 3 = 31 \]

Your final results are:

• \( b = 3 \)
• \( s = 31 \)

Well done! If you have any other questions or problems you'd like to work on, feel free to ask!

Answer 4

Write an equation that represents this situation. Use the variable h
for hardcover books and the variable p
for paperbacks

Answer 5

Sure! To create an equation representing a situation involving hardcover books (denoted by \( h \)) and paperbacks (denoted by \( p \)), we first need to establish the context or specific quantities involved in the situation.

Here are a couple of examples of how you might construct the equations, depending on the situation you are describing:

Example 1: Total Book Count

If the total number of books is a known value, say 50, then the equation could be: \[ h + p = 50 \]

Example 2: Cost Representation

If hardcover books cost $20 each and paperbacks cost $10 each, and the total cost is a known value (e.g., $300), the equation would be: \[ 20h + 10p = 300 \]

Example 3: Ratio of Hardcover to Paperbacks

If you want to maintain a specific ratio between hardcover and paperback books, for instance, for every 2 hardcover books, there are 3 paperbacks, the equation could be: \[ \frac{h}{2} = \frac{p}{3} \quad \text{or} \quad 3h = 2p \]

If you provide more specific details about the situation, I can help create a more tailored equation. Let me know what additional details you might have!

Answer 6

Carlos found 5 hardcover books that he really wants to buy. If he bought these 5 hardcover books, how many paperbacks could he buy?

Answer 7

To create an equation that describes the situation involving Carlos and his purchases, we can set up the problem based on the following assumptions:

1. Let \( h \) be the number of hardcover books Carlos wants to buy.
2. Let \( p \) be the number of paperback books Carlos wants to buy.
3. We'll assume there is a budget constraint, which we can denote as \( B \) for the total amount of money Carlos is willing to spend.
4. Let \( C_h \) be the cost of each hardcover book, and \( C_p \) be the cost of each paperback.

Assuming you have a budget but haven’t specified it, here's a hypothetical formulation:

Example Setup

• Cost of a hardcover book: \( C_h \) (for example, $20)
• Cost of a paperback: \( C_p \) (for example, $10)
• Total budget: \( B \) (for example, $100)

Equation

1. Carlos wants to buy 5 hardcover books, so: \[ h = 5 \]

2. The equation representing the budget, considering his purchase, would be: \[ C_h \cdot h + C_p \cdot p \leq B \] Substituting \( h \): \[ 20 \cdot 5 + 10 \cdot p \leq B \] \[ 100 + 10p \leq B \]

If we assume \( B = 100 \): \[ 100 + 10p \leq 100 \] \[ 10p \leq 0 \] \[ p \leq 0 \]

This means that if the budget is exactly $100, Carlos can't afford any paperbacks after buying the 5 hardcover books.

If Budget is Greater

If Carlos has a greater budget, e.g., $150: \[ 100 + 10p \leq 150 \] \[ 10p \leq 50 \] \[ p \leq 5 \]

In this scenario, with a budget of $150, Carlos could buy a maximum of 5 paperbacks after purchasing the 5 hardcover books.

Conclusion

To determine how many paperbacks Carlos can buy, you need to specify the cost of hardcover and paperback books and the total budget. With those details, the equation will help you find the number of paperbacks he can afford after buying the hardcover books. If you provide these values, I can create a more precise equation for you!

Answer 8

In the end, Carlos bought a total of 22 books. Write another equation using h
and p
that describes this situation.

Answer 9

Given that Carlos bought a total of 22 books, we can formulate an equation to represent the total number of books he purchased in terms of hardcover books \( h \) and paperbacks \( p \).

Since we know that \( h = 5 \) (the number of hardcover books he purchased), we can express the total number of books he bought as follows:

Equation:

\[ h + p = 22 \]

Substituting for \( h \):

Since we know Carlos bought 5 hardcover books (i.e., \( h = 5 \)), we can substitute that value into the equation:

\[ 5 + p = 22 \]

Solving for \( p \):

To find out how many paperbacks \( p \) he bought, we can solve the equation:

\[ p = 22 - 5 \] \[ p = 17 \]

Final Expressions:

The equation representing the total number of books Carlos bought is: \[ h + p = 22 \]

And since \( h = 5 \), he subsequently purchased \( p = 17 \) paperbacks.

So, in summary:

• Total books equation: \( h + p = 22 \)
• Number of paperbacks \( p = 17 \) when \( h = 5 \).

Answer 10

Kalani is planning a birthday party at the science center. It will cost $120 to reserve the party, plus $11.00 per child and $6.50 per adult. There needs to be at least one adult and at least one child at the party. She has budgeted $300 for the party and that is the maximum amount she wants to spend.

[To type inequality symbols ≤
or ≥
, type <= or >=.]



A) Write an inequality to represent this situation. Use c
to represent the number of children attending and use a
to represent the number of adults attending.

Answer 11

To write the inequality representing Kalani's birthday party budget, we need to account for the costs associated with reserving the party, the costs per child, and the costs per adult.

Given Values:

• Fixed cost to reserve the party: $120
• Cost per child: $11.00
• Cost per adult: $6.50
• Total budget: $300

Variables:

• Let \( c \) be the number of children.
• Let \( a \) be the number of adults.

Expression for Total Cost:

The total cost \( T \) for the party can be expressed as: \[ T = 120 + 11c + 6.50a \]

Inequality for the Budget:

Since Kalani wants to stay within her budget of $300, we can write the inequality as: \[ 120 + 11c + 6.50a \leq 300 \]

Rearranging the Inequality:

To make it a bit clearer, we can subtract 120 from both sides: \[ 11c + 6.50a \leq 180 \]

Additional Constraints:

Since there needs to be at least one adult and one child at the party, we also have the following constraints: \[ c \geq 1 \] \[ a \geq 1 \]

Final Representation:

The complete representation of the situation, including the budget inequality and the constraints, is:

1. Budget Inequality: \[ 11c + 6.50a \leq 180 \]

2. Constraints: \[ c \geq 1 \] \[ a \geq 1 \]

This set of inequalities and constraints effectively represents Kalani's budget situation for the party.

Answer 12

copy and paste able the budget inequality and the Constraints

Answer 13

Sure! Here are the budget inequality and the constraints in a copy-and-pasteable format:

Budget Inequality:

11c + 6.50a <= 180

Constraints:

c >= 1
a >= 1

Feel free to copy and paste this as needed!

Answer 14

Solve the system of equations using substitution.
Type the ordered pair(s) (x,y)
that are the solution(s) to the system of equations.

Answer 15

To solve a system of equations using substitution, I'll need to know the specific equations you want me to work with. Please provide the equations, and I'll be happy to help you solve them and type out the ordered pair(s) \( (x, y) \) for the solution!

Answer 16

y+4=2x
y=(x−2)2−3

Answer 17

To solve the system of equations using substitution, we can take the two equations you provided:

1. \( y + 4 = 2x \) (Equation 1)
2. \( y = (x - 2)^2 - 3 \) (Equation 2)

Step 1: Solve for \( y \) in Equation 1

From Equation 1, rearranging for \( y \):

\[ y = 2x - 4 \]

Step 2: Substitute \( y \) in Equation 2

Now that we have \( y \) in terms of \( x \), we can substitute \( y \) into Equation 2:

\[ 2x - 4 = (x - 2)^2 - 3 \]

Step 3: Expand and simplify

Expanding the right side:

\[ 2x - 4 = (x^2 - 4x + 4) - 3 \] \[ 2x - 4 = x^2 - 4x + 1 \]

Step 4: Rearranging the equation

Now, let's rearrange this into standard form:

\[ 0 = x^2 - 4x + 1 - 2x + 4 \] \[ 0 = x^2 - 6x + 5 \]

Step 5: Factor or use the quadratic formula

Next, we can factor this quadratic:

\[ 0 = (x - 1)(x - 5) \]

Setting each factor to zero gives us the solutions for \( x \):

• \( x - 1 = 0 \) → \( x = 1 \)
• \( x - 5 = 0 \) → \( x = 5 \)

Step 6: Solve for \( y \)

Now we will find the corresponding \( y \) values for each \( x \) value using \( y = 2x - 4 \):

1. For \( x = 1 \): \[ y = 2(1) - 4 = 2 - 4 = -2 \] This gives us the ordered pair \( (1, -2) \).

2. For \( x = 5 \): \[ y = 2(5) - 4 = 10 - 4 = 6 \] This gives us the ordered pair \( (5, 6) \).

Final Solutions

The ordered pairs that are the solutions to the system of equations are:

1. \( (1, -2) \)
2. \( (5, 6) \)

Therefore, the solution set is: \[ (1, -2), (5, 6) \]

Answer 18

Given the constraints of the scenario, select all of the options that are nonviable solutions to the inequality.(3 points)
Responses

a=12, c=2
a=12, c=2

a=5.6, c=15
a=5.6, c=15

a=18, c=−3
a=18, c=−3

a=0, c=20