R = 0.01/2 =0.005 meters radius
A = pi R^2 = 3.14 * (0.005)^2 = 7.85 * 10^-5 m^2
F/ (7.85*10^-5) = 4.2 * 10^8
F = 33 *10^3 = 33,000 Newtons
Steel will rapture if subjected to a shear stress of more that about 4.2 * 10 8 N/m2. What sideward
force is necessary to shear a steel bolt 1 cm in diameter?
1 answer
1 answer