Let's analyze the system of equations you provided step by step to determine what each statement might imply.
- Equations:
- The first equation is \( y = 3x + 7 \).
- The second equation appears to have typographical errors, but if we simplify the expression \( x = -3x - x \), it simplifies to \( x = -4x \) or \( 5x = 0 \), which gives \( x = 0 \). Therefore, let’s assume the second equation is \( y = -3x \).
Now we can analyze the two equations we understood:
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\( y = 3x + 7 \) (slope = 3, y-intercept = 7)
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\( y = -3x \) (slope = -3, y-intercept = 0)
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Statements Analysis:
- "The equations have different slopes and different y-intercepts." True: The slopes are 3 and -3, and their y-intercepts are 7 and 0, respectively.
- "Does the system have one solution at negative 3, 7?" False: The point (-3, 7) is on the first equation, but not on the second.
- "Both equations have a slope of negative 3." False: The first has a slope of 3, the second has a slope of -3.
- "The system has no solution because the lines are parallel." False: The slopes are different (3 and -3), so they intersect at one point.
- "Both equations have a slope of negative 3, and they share the same y-intercept." False.
- "The system has an infinite number of solutions because they are identical lines." False: The lines are not identical since they have different slopes and y-intercepts.
- "The equations have different slopes but they share the same y-intercept (0, 3)." False: They do not share the same y-intercept; they intercept the y-axis at different points.
- "This system has one solution at (0, -3)." False: At \( x = 0 \), \( y = -3 \) for the second equation, but not the first.
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Conclusion: The correct conclusion about the system of equations is that it has one solution because the slopes are different. To find the intersection point:
Setting the equations equal: \[ 3x + 7 = -3x \]
Now solve for \( x \): \[ 6x = -7 \] \[ x = -\frac{7}{6} \]
Then substitute \( x \) into either equation to find \( y \): \[ y = 3\left(-\frac{7}{6}\right) + 7 \] \[ y = -\frac{21}{6} + \frac{42}{6} \] \[ y = \frac{21}{6} \]
So, there is one intersection point at \( \left(-\frac{7}{6}, \frac{21}{6}\right) \).
Thus, the correct statement about this system is that it has one solution, somewhere other than (0, -3) or (-3, 7).