Asked by Linda
State the domain and range of the function
f(x) = 2sin(sqrt(3x-1)) + 3
Why is this so difficult?
f(x) = 2sin(sqrt(3x-1)) + 3
Why is this so difficult?
Answers
Answered by
Steve
no idea. Just take it step by step.
domain of √x is x>=0
so, the domain of √(3x-1) is 3x-1 >= 0, or x >= 1/3
the domain of sin(x) is all reals, so
the domain of sin(√(3x-1)) is the domain of √(3x-1), or x >= 1/3
domain of √x is x>=0
so, the domain of √(3x-1) is 3x-1 >= 0, or x >= 1/3
the domain of sin(x) is all reals, so
the domain of sin(√(3x-1)) is the domain of √(3x-1), or x >= 1/3
Answered by
Steve
of course, the range is just the same as the range of 2sin(x)+3: [1,5]
http://www.wolframalpha.com/input/?i=2sin(sqrt(3x-1))+%2B+3
http://www.wolframalpha.com/input/?i=2sin(sqrt(3x-1))+%2B+3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.