no idea. Just take it step by step.
domain of √x is x>=0
so, the domain of √(3x-1) is 3x-1 >= 0, or x >= 1/3
the domain of sin(x) is all reals, so
the domain of sin(√(3x-1)) is the domain of √(3x-1), or x >= 1/3
State the domain and range of the function
f(x) = 2sin(sqrt(3x-1)) + 3
Why is this so difficult?
2 answers
of course, the range is just the same as the range of 2sin(x)+3: [1,5]
http://www.wolframalpha.com/input/?i=2sin(sqrt(3x-1))+%2B+3
http://www.wolframalpha.com/input/?i=2sin(sqrt(3x-1))+%2B+3
2 answers