grab you calculator. start with 2^3, that should be 8, so 2 is too hight. So now punchin
1.9^3, 6.86 that is too low. So now try
1.95^3 7.41, so it is too high, so punchin
1.93^3, 7.19, still too hight, so punchin
1.92^3 7.08 still too hight
punchin
1.913^3 7.0008 still very slightly too high, but getting close to four decimal places...
punchin
1.9128^3 6.998 too low, so punchin
1.9129^3 6.9996, so up again
punchin
1.91293^3 6.999987 that is 7 to four decimal places. Then compare it to your calculator 7^(1/3) results.
Starting with an initial guess of x=2, use Newton’s method to approximate (Third root of 7). Stop the iterations when your approximations converge to four decimal places of accuracy. Compare with the approximation provided by your calculator
I'm so stuck
1 answer
1 answer