starting from rest an object hits the water with a speed of 60 km/h from what height did the object start from above the water

Answer 1

To find the height from which the object was dropped, we can use the equation of motion:

v^2 = u^2 + 2as

where:
v = final velocity = 60 km/h = 16.67 m/s
u = initial velocity = 0 m/s (object starts from rest)
a = acceleration due to gravity = 9.81 m/s^2
s = distance or height

Plugging in the values, we get:

(16.67)^2 = (0)^2 + 2(9.81)s
278.9 = 19.62s
s = 14.21 meters

Therefore, the object was dropped from a height of 14.21 meters above the water.