M*g = 93 * 9.8 = 911.4 N. = Wt. of firefighter.
Mg-Fk = M*a.
911.4 - 710 = 98*a, a = ?.
V = Vo^2 + 2a*d.
3.2 = 0 + 2a*d, d = ?.
Starting from rest, a 93-kg firefighter slides down a fire pole. The average frictional force everted on him by the pole has a magnitude of 710 N, and his speed at the bottom of the pole is 3.2 m/s. How far did he slide down the pole?
What equation do you use to determine this.
1 answer