Starting from 150 ft away, your friend skates toward you and then passes you. She skates at a constant speed of 20 Bs. Her distance d from you in feet after t seconds is given by d = |150 - 201| At what times is she 110 from you?

Answer 1

The distance equation given is incorrect. Let's correct it:

Since she starts from 150 ft away, her initial distance from you, $d_0$, is 150 ft. We can represent her distance from you as a function of time ($t$) using the equation:

$d = d_0 - 20t$

Now, we want to find the times ($t$) when she is 110 ft from you. Substituting $d=110$ into the equation, we have:

$110 = 150 - 20t$

Rearranging the equation:

$20t = 150 - 110$

$20t = 40$

$t = \frac{40}{20} = 2$

Therefore, she is 110 ft away from you at $t = 2$ seconds.