To find the times when she is 50 ft away from you, we need to set the distance d equal to 50 ft and solve for t.
Given, d = |150 - 20t|
Setting d = 50, we have:
50 = |150 - 20t|
Now, we need to solve this equation for t.
If 150 - 20t is positive, it equals 50:
150 - 20t = 50
Subtracting 150 from both sides:
-20t = 50 - 150
-20t = -100
Dividing by -20:
t = -100 / -20
t = 5
So, if 150 - 20t is positive, she is 50 ft away from you after 5 seconds.
Now, if 150 - 20t is negative, it equals -50:
150 - 20t = -50
Subtracting 150 from both sides:
-20t = -50 - 150
-20t = -200
Dividing by -20:
t = -200 / -20
t = 10
So, if 150 - 20t is negative, she is 50 ft away from you after 10 seconds.
Therefore, she is 50 ft away from you after 5 seconds and 10 seconds.
Starting from
150 ft away, your friend skates toward you and then passes you. She skates at a constant speed of
20 ft/s. Her distance d from you in feet after t seconds is given by d
=|150−20|t. At what times is she
50 ft from you?
She is
50 ft away from you after
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