Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|. At what times is the bike 15 feet away from the checkpoint.

Question

a. 4.6 sec and 9.2 sec
b. 2.9 sec and 5.8 sec
c. 4.6 sec and 5.8 sec
d. 2.9 sec and 3.3 sec

Answer 1

d = 130 - 25 t
or
d = -(130 -25 t) = -130 + 25 t

Answer 2

so what's the answer?

Answer 3

hey, I think you can solve those two equations !

Answer 4

your not helpful Damon just say the answer

Answer 5

For this question you can say d = 15 feet so we need the t then you can say : 
15 = l 130 - 25t l ⇒ because of the absolute value you should say : 
1) 130 - 25t = 15  ⇒ -25t = 15 - 130 ⇒ - 25t = -115 ⇒ t = 115/25 = 4.6 sec 

2) 130 - 25t = - 15 ⇒ -25t = -15 - 130 ⇒ -25t = - 145 ⇒ t = 145/25 = 5.8 sec 
so the answer is c :))
i hope this is helpful 
have a nice day 

Answer 6

Thank you toof.

Answer 7

damon is not helpful=confirmed

Answer 8

Anyone have all the answers for the test?????

Answer 9

I agree Damon you helped me

Answer 10

he didn't help at all what r u on abt😭