Asked by Ous
StartFraction y squared minus 3 y plus 2 Over y squared plus 5 y minus 6 EndFraction
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Answered by
GPT-4o mini
To simplify the expression
\[
\frac{y^2 - 3y + 2}{y^2 + 5y - 6},
\]
we can start by factoring both the numerator and the denominator.
**Step 1: Factor the numerator \(y^2 - 3y + 2\)**
We need to find two numbers that multiply to \(2\) (the constant term) and add to \(-3\) (the coefficient of \(y\)). The numbers \(-1\) and \(-2\) satisfy these conditions.
Thus, we can factor the numerator:
\[
y^2 - 3y + 2 = (y - 1)(y - 2).
\]
**Step 2: Factor the denominator \(y^2 + 5y - 6\)**
Next, we look for two numbers that multiply to \(-6\) and add to \(5\). The numbers \(6\) and \(-1\) fit these requirements.
So, we factor the denominator:
\[
y^2 + 5y - 6 = (y + 6)(y - 1).
\]
**Step 3: Rewrite the expression**
Now, we substitute the factored forms back into the expression:
\[
\frac{(y - 1)(y - 2)}{(y + 6)(y - 1)}.
\]
**Step 4: Simplify the expression**
We notice that \((y - 1)\) appears in both the numerator and the denominator, and we can cancel it out (provided \(y \neq 1\)):
\[
\frac{(y - 2)}{(y + 6)} \quad \text{for } y \neq 1.
\]
**Final Result:**
Thus, the simplified form of the expression is:
\[
\frac{y - 2}{y + 6} \quad \text{for } y \neq 1.
\]
\[
\frac{y^2 - 3y + 2}{y^2 + 5y - 6},
\]
we can start by factoring both the numerator and the denominator.
**Step 1: Factor the numerator \(y^2 - 3y + 2\)**
We need to find two numbers that multiply to \(2\) (the constant term) and add to \(-3\) (the coefficient of \(y\)). The numbers \(-1\) and \(-2\) satisfy these conditions.
Thus, we can factor the numerator:
\[
y^2 - 3y + 2 = (y - 1)(y - 2).
\]
**Step 2: Factor the denominator \(y^2 + 5y - 6\)**
Next, we look for two numbers that multiply to \(-6\) and add to \(5\). The numbers \(6\) and \(-1\) fit these requirements.
So, we factor the denominator:
\[
y^2 + 5y - 6 = (y + 6)(y - 1).
\]
**Step 3: Rewrite the expression**
Now, we substitute the factored forms back into the expression:
\[
\frac{(y - 1)(y - 2)}{(y + 6)(y - 1)}.
\]
**Step 4: Simplify the expression**
We notice that \((y - 1)\) appears in both the numerator and the denominator, and we can cancel it out (provided \(y \neq 1\)):
\[
\frac{(y - 2)}{(y + 6)} \quad \text{for } y \neq 1.
\]
**Final Result:**
Thus, the simplified form of the expression is:
\[
\frac{y - 2}{y + 6} \quad \text{for } y \neq 1.
\]
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