StartFraction 3 left parenthesis x minus 6 right parenthesis Over 2 EndFraction

greater than or equalsStartFraction 2 x Over 7 EndFraction
minus12

The solution as an inequality is

1 answer

To solve the inequality

\[ \frac{3(x - 6)}{2} \geq \frac{2x}{7} - 12, \]

first, we clear the fractions by multiplying both sides by 14 (the least common multiple of 2 and 7):

\[ 14 \cdot \frac{3(x - 6)}{2} \geq 14 \cdot \left(\frac{2x}{7} - 12\right). \]

This simplifies to:

\[ 7 \cdot 3(x - 6) \geq 4x - 168. \]

Now simplify the left side:

\[ 21(x - 6) \geq 4x - 168. \]

Distributing 21 gives us:

\[ 21x - 126 \geq 4x - 168. \]

Next, isolate \(x\) by subtracting \(4x\) from both sides:

\[ 21x - 4x - 126 \geq -168. \]

This simplifies to:

\[ 17x - 126 \geq -168. \]

Now add \(126\) to both sides:

\[ 17x \geq -168 + 126. \]

Calculating the right side yields:

\[ 17x \geq -42. \]

Finally, divide both sides by 17:

\[ x \geq -\frac{42}{17}. \]

Thus, the solution to the inequality is

\[ x \geq -\frac{42}{17}. \]