start fraction 1 over 3x plus 9 end fraction minus start fraction 2 over x plus 3 end fraction equals 2

Answer 1

To solve this equation, we first need to find a common denominator for the fractions on the left side. The common denominator in this case is (3x + 9)(x + 3).

So, the equation becomes:

(start fraction 1 over 3x + 9 end fraction) - (start fraction 2 over x + 3 end fraction) = 2
(start fraction (x + 3) over (3x + 9)(x + 3) end fraction) - (start fraction 6 over (3x + 9)(x + 3) end fraction) = 2

Now, we can combine the fractions:

(start fraction x + 3 - 6 over (3x + 9)(x + 3) end fraction) = 2

Simplifying the numerator, we get:

(start fraction x - 3 over (3x + 9)(x + 3) end fraction) = 2

We can now set up the equation:

x - 3 = 2(3x + 9)(x + 3)

Solve for x to find the value of x.