Standard form of hyperbola: Hyperbola: Vertices: (9,9), (9, -7) Foci: (9, 1 + 4 sqrt 13), (9, 1 - 4 sqrt 13)?

Question

Standard form Ellipse: vertices: (2 sqrt 10, -10), (-2 sqrt 10, -10) foci: (sqrt 30, -10), (-sqrt 30, -10)?

Answer 1

the center is at (9,1)
a=8
c=4?13
b^2 = c^2-a^2 = 208-64=144

axis is vertical,so

(y-1)^2/144 - (x-9)^2/64 = 1

http://www.wolframalpha.com/input/?i=hyperbola+(y-1)%5E2%2F144+-+(x-9)%5E2%2F64+%3D+1

do the other in like wise.

Answer 2

Oops I got a and b reversed.

http://www.wolframalpha.com/input/?i=hyperbola+(y-1)%5E2%2F64+-+(x-9)%5E2%2F144+%3D+1