squareroot2/2+squareroot2

1 answer

To simplify the expression \(\frac{\sqrt{2}}{2} + \sqrt{2}\), you can first express \(\sqrt{2}\) with a common denominator:

\[ \sqrt{2} = \frac{\sqrt{2} \cdot 2}{2} = \frac{2\sqrt{2}}{2} \]

Now, substitute this back into the expression:

\[ \frac{\sqrt{2}}{2} + \sqrt{2} = \frac{\sqrt{2}}{2} + \frac{2\sqrt{2}}{2} \]

Combine the fractions:

\[ \frac{\sqrt{2} + 2\sqrt{2}}{2} = \frac{3\sqrt{2}}{2} \]

So, the simplified result is:

\[ \frac{3\sqrt{2}}{2} \]