Asked by kamakshi
sqrt sin(30)+sin(45)+sin(60)+sin(75).....infnity
Answers
Answered by
Steve
since sin(180+x) = -sin(x) this series cannot be evaluated. Or, it can be evaluated in a variety of different ways, giving different answers.
The ratio test fails.
The ratio test fails.
Answered by
Reiny
first assumption: the square root is over the whole thing
2nd:
it would be nice if the series has included the terms
sin 0 and sin 15
well, let's put them in
so we have
√ ( -sin 0 - sin 15 + (sin 0 + sin15 + sin30 + ... sin 345) + (sin 360 + sin 375 + .... sin 705) + (......) )
as Steve noted , we have opposite terms in each of the set of brackets
e.g.
sin 0 + sin 15 + .... + sin 345) = 0
so is each of the rest of the brackets
since the series goes to infinity,
I see the series as
√( 0 - sin 15 + 0+0+0+....)
which of course is not a real number, since -sin15° is negative,
and as Steve said , it cannot be evaluated.
2nd:
it would be nice if the series has included the terms
sin 0 and sin 15
well, let's put them in
so we have
√ ( -sin 0 - sin 15 + (sin 0 + sin15 + sin30 + ... sin 345) + (sin 360 + sin 375 + .... sin 705) + (......) )
as Steve noted , we have opposite terms in each of the set of brackets
e.g.
sin 0 + sin 15 + .... + sin 345) = 0
so is each of the rest of the brackets
since the series goes to infinity,
I see the series as
√( 0 - sin 15 + 0+0+0+....)
which of course is not a real number, since -sin15° is negative,
and as Steve said , it cannot be evaluated.
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