\sqrt{i} in polar form can be written as r(\cos \theta + i \sin \theta), where r is a real number and 0 \leq \theta \leq \frac{\pi}{2}. What is the measure of \theta (in degrees)?

1 answer

i = (1,pi/2)
√i = (1,pi/4)
Similar Questions
  1. Suppose that \Theta takes values in [0,1] and its PDF is of the formf_{\Theta }(\theta )= a\theta (1-\theta )^2,\ \ \
    1. answers icon 1 answer
    1. answers icon 6 answers
  2. What values for theta(0 <= theta <= 2pi) satisfy the equation?2 sin theta cos theta + sqrt 3 cos theta = 0 a. pi/2, 4pi/3,
    1. answers icon 2 answers
    1. answers icon 5 answers
more similar questions