I am not sure what you want but
8 = 2^3
125 = 5^3
64 = 2^6 = 4^3
(2x/5)^3 + (4/y)^3
but a^3 + b^3 = (a+b)(a^2-ab+b^2)
(2x/5+4/y)(4x^2/25-8x/y+16/y^2)
Special factorization
I know someone has helped me with this before, but I'm really stuck on how to attack these two problems
[(8x^3)/125]+[64/(y^3)]
X^2-8xy+16y^2-25
8 answers
maybe complete the square?
(x^2-8xy+16y^2) -16y^2 +16y^2-25
(x-4y)^2 - 5^2
(a-b)^2 = (a+b)(a-b)
(x-4y+5)(x-4y+5)
(x^2-8xy+16y^2) -16y^2 +16y^2-25
(x-4y)^2 - 5^2
(a-b)^2 = (a+b)(a-b)
(x-4y+5)(x-4y+5)
Is it not 8x/5y not 8x/y. I'm only basing this off of what you gave me
Yes, you are right
and in the second one a sign error
(x-4y+5)(x-4y-5)
(x-4y+5)(x-4y-5)
Thank you sir!!! And thanks for being awake(unless you're not from the U.S)
You are welcome and I am from a fishing town north of Boston where we rise early.
Pretty darn early, and I'm 30 mins away from philly