Sove for y

(ey/n) +k=t

a
y=n(t+k)/e

b
y=(t+k)/en

c
y=n(t-k)/e

1 answer

To solve for \( y \) in the equation

\[ \frac{ey}{n} + k = t, \]

we start by isolating \( \frac{ey}{n} \):

  1. Subtract \( k \) from both sides:

\[ \frac{ey}{n} = t - k. \]

  1. Next, multiply both sides by \( n \):

\[ ey = n(t - k). \]

  1. Finally, divide both sides by \( e \):

\[ y = \frac{n(t - k)}{e}. \]

So, the correct answer is:

\[ c \quad y = \frac{n(t - k)}{e}. \]