Sorryy but I still don't understand will you show the calculations for my previous question
2 answers
The way this system works is that you should have typed your response at the old question. I don't remember the numbers well enough. Anyway, look at your original post; I've given detailed work there.
How many grams of NaOh are required to neutralize 15.0mL 0f 0.85M HCl. Show calculations please
0 answers