Asked by coolcat
sorry the first one I put in had a typo
cosx/1-tanx + sinx/1-cotx = sinx +cosx
cosx/1-tanx + sinx/1-cotx = sinx +cosx
Answers
Answered by
Reiny
prove that it is an identity I assume ??
General rule to start:
1. begin with the complicated side and simplify it
2. change all trig ratios to sines and cosines if possible, unless an obvious relation can be seen
LS
= cosx/(1-sinx/cosx) + sinx/(1 - cosx/sinx)
= cosx/[(cosx - sinx)/cosx] + sinx/[(sinx-cosx)/sinx]
= cosx (cosx)/(cosx - sinx) - sinx (cosx - sinx)
= (cos^2 x - sin^2 x)/(cosx - sinx)
= (cosx - sinx)(cosx+ sinx)/(cosx - sinx)
= cosx + sinx
= RS
General rule to start:
1. begin with the complicated side and simplify it
2. change all trig ratios to sines and cosines if possible, unless an obvious relation can be seen
LS
= cosx/(1-sinx/cosx) + sinx/(1 - cosx/sinx)
= cosx/[(cosx - sinx)/cosx] + sinx/[(sinx-cosx)/sinx]
= cosx (cosx)/(cosx - sinx) - sinx (cosx - sinx)
= (cos^2 x - sin^2 x)/(cosx - sinx)
= (cosx - sinx)(cosx+ sinx)/(cosx - sinx)
= cosx + sinx
= RS
Answered by
Reiny
5th last line should say
= cosx (cosx)/(cosx - sinx) - sinx (sinx)(cosx - sinx)
= cosx (cosx)/(cosx - sinx) - sinx (sinx)(cosx - sinx)
Answered by
coolcat
Thanks!
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