Sorry I've tried 3 different ways to answer this and all have been wrong, please help me out!

The moment of inertia of a 1.1 kg bicycle wheel rotating about its center is 0.15 kg*m^2

What is the radius of this wheel, assuming the weight of the spokes can be ignored?

4 answers

I would model the wheel as a hoop>

Mr^2=.15
r= sqrt (.15/1.1)= 37 cm
It would be nice if you posted your three ways to calculate the quantity, and the values that you obtained.

Moment of inertia
=Σmr²
In this case, the weight is all distributed at the rim, ignoring spokes, so
1.1 kg r²=0.15 kg-m²
Solve for r.
Thank you so much guys!!!
You're welcome, Sally!
Similar Questions
    1. answers icon 1 answer
  1. My problem is evaluate the expression -1 11/16 - (-4 1/6)?1) -27/16 + 25/6 = -81/48 + 200/48 = 119/48 = 2 23/48 2) -1 33/48 + 4
    1. answers icon 1 answer
  2. QuestionHow many ways can you choose 7 coins consisting of dimes and nickels so that their total value does not exceed half a
    1. answers icon 1 answer
  3. Calculate the pH of a 5.90 10-3 M solution of H2SO4I have tried doing this as pH=-log[H+] and also by multiplying the Molarity
    1. answers icon 2 answers
more similar questions