I would model the wheel as a hoop>
Mr^2=.15
r= sqrt (.15/1.1)= 37 cm
Sorry I've tried 3 different ways to answer this and all have been wrong, please help me out!
The moment of inertia of a 1.1 kg bicycle wheel rotating about its center is 0.15 kg*m^2
What is the radius of this wheel, assuming the weight of the spokes can be ignored?
4 answers
It would be nice if you posted your three ways to calculate the quantity, and the values that you obtained.
Moment of inertia
=Σmr²
In this case, the weight is all distributed at the rim, ignoring spokes, so
1.1 kg r²=0.15 kg-m²
Solve for r.
Moment of inertia
=Σmr²
In this case, the weight is all distributed at the rim, ignoring spokes, so
1.1 kg r²=0.15 kg-m²
Solve for r.
Thank you so much guys!!!
You're welcome, Sally!
1 answer