The mols HCl remaining in the flask after the tablet has been neutralized is just M NaOH x L NaOH = mols NaOH = mols HCl because that part of the reaction is
HCl + NaOH ==> NaCl + H2O
Sorry if I confused you. I miss-wrote my question.
My question was: How can I determine the concentration of HCl remaining in the flask.
I calculated the # of moles of HCl neutralized by the tablet which was around 0.014 M.
I don't understand the steps needed to calculate the concentration of HCl remaining in the flask.
Given:
Con. of HCl: 0.14M
Volume added:100mL
Con. of NaOH:0.145M
Weight of Tablet: 1.3g
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