For angle:
tan_1(Fy/Fx)
Sorry, I didn't see that there was a second part to the question. What is the difference between this one and the previous question I posted?
The x and y components of a certain force are measured and found to be Fx = 68 ± 3N and Fy = 42 ± 2 N, respectively. Calculate the error associated with the direction (angle with respect to the X-axis, NOTE: this angle is NOT with respect to the Y-axis) of this force?
2 answers
The difference is at the end, it's asking for the error in direction (angle).
Apply the same method in your other post.
Give it a try.
Apply the same method in your other post.
Give it a try.