Asked by ASDFGHJKL;
Sorry for repeated questions, but this is my last problem:
s = ut + 1/2(gt)
The "t" for "gt" is squared, and the subject of the formula is "u".
Thank you very much (and please include workings).
s = ut + 1/2(gt)
The "t" for "gt" is squared, and the subject of the formula is "u".
Thank you very much (and please include workings).
Answers
Answered by
ASDFGHJKL;
Sorry for wrong problem, it should be:
(1/2)*(gt)
(1/2)*(gt)
Answered by
Jai
when you want a variable to be squared you use this symbol, ^ , which means "raised to".
in the problem,
s = ut + (1/2)*(g*t^2)
s - (1/2)*(g*t^2) = ut
[ s - (1/2)*(g*t^2) ]/t = u, or
u = [ s - (1/2)*(g*t^2) ]/t
in the problem,
s = ut + (1/2)*(g*t^2)
s - (1/2)*(g*t^2) = ut
[ s - (1/2)*(g*t^2) ]/t = u, or
u = [ s - (1/2)*(g*t^2) ]/t
Answered by
Damon
I bet you mean:
s = u t + (1/2) g t^2
which is a falling object with initial speed down u under gravitational acceleration g. s is distance.
s - (1/2) g t^2 = u t
u = [ s - (1/2) g t^2 ] /t
or
u = s/t - (1/2) g t
s = u t + (1/2) g t^2
which is a falling object with initial speed down u under gravitational acceleration g. s is distance.
s - (1/2) g t^2 = u t
u = [ s - (1/2) g t^2 ] /t
or
u = s/t - (1/2) g t
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