To determine which of the proposed values are solutions to the compound inequality \( -2 \leq 2x - 2 < 8 \), we first solve the inequality.
Step 1: Break it down into two parts
-
Solve the first part:
\(-2 \leq 2x - 2\)Add 2 to both sides:
\(-2 + 2 \leq 2x - 2 + 2\)
\(0 \leq 2x\)
Divide by 2:
\(0 \leq x\)
which means \(x \geq 0\). -
Solve the second part:
\(2x - 2 < 8\)Add 2 to both sides:
\(2x - 2 + 2 < 8 + 2\)
\(2x < 10\)
Divide by 2:
\(x < 5\).
Step 2: Combine the inequalities
From the two parts, we have:
\[ 0 \leq x < 5 \]
or equivalently,
\[ x \in [0, 5) \]
Step 3: Check the proposed solutions
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Sophie says that \(-2\) is a solution.
Check if \(-2\) is within the interval \([0, 5)\):
\(-2\) is not in \([0, 5)\). -
Adola says that \(5\) is a solution.
Check if \(5\) is within the interval \([0, 5)\):
\(5\) is not included in the interval because of the strict inequality. -
Gilly says that \(2\) is a solution.
Check if \(2\) is within the interval \([0, 5)\):
\(2\) is indeed in the interval \([0, 5)\).
Conclusion
The only correct solution among the three is provided by Gilly. Therefore, the answer is:
3 for Gilly.