To solve the compound inequality \(-2 \leq 2x - 2 < 8\), let's analyze it step by step.
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First part: Solve \(-2 \leq 2x - 2\)
Add 2 to both sides: \[ 0 \leq 2x \] Divide both sides by 2: \[ 0 \leq x \quad \text{or} \quad x \geq 0 \]
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Second part: Solve \(2x - 2 < 8\)
Add 2 to both sides: \[ 2x < 10 \] Divide both sides by 2: \[ x < 5 \]
Now we combine the results from both parts: \[ 0 \leq x < 5 \]
This means the solution set for \(x\) is: \[ x \in [0, 5) \]
Now let's evaluate the claims made by Sophie, Adola, and Gilly:
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Sophie says that \(-2\) is a solution. \(-2\) is not in the interval \([0, 5)\) (FALSE).
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Adola says that \(5\) is a solution. \(5\) is not in the interval \([0, 5)\) (FALSE).
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Gilly says that \(2\) is a solution. \(2\) is in the interval \([0, 5)\) (TRUE).
Thus, Gilly is the one who is correct.
The answer is 3.