Let's solve the compound inequality \(-2 \leq 2x - 2 < 8\).
We can break this down into two separate inequalities:
- \(-2 \leq 2x - 2\)
- \(2x - 2 < 8\)
Starting with the first inequality:
\(-2 \leq 2x - 2\)
Add 2 to both sides:
\[ 0 \leq 2x \]
Divide both sides by 2:
\[ 0 \leq x \quad \text{or} \quad x \geq 0 \]
Now, for the second inequality:
\(2x - 2 < 8\)
Add 2 to both sides:
\[ 2x < 10 \]
Divide both sides by 2:
\[ x < 5 \]
Combining both results, we have:
\[ 0 \leq x < 5 \]
This means that \(x\) can take any value from 0 up to (but not including) 5.
Now let's check each person's claim:
-
Sophie claims \(x = -2\):
- \(-2\) is not in the interval \([0, 5)\), so Sophie is incorrect.
-
Adola claims \(x = 5\):
- \(5\) is not in \([0, 5)\) (it is excluded), so Adola is incorrect.
-
Gilly claims \(x = 2\):
- \(2\) is in the interval \([0, 5)\), so Gilly is correct.
Thus, the person who is correct is person 3 (Gilly).