Sophia was solving the following quadratic equation by factoring: `x^{2}-8x-20=0. Which choice shows the correctly factored form of this equation?

(x-5) (x-4) =0
(x-5) (x+4) =0
(x-10) (x-2) =0
(x-10) (x+2) =0

1 answer

To factor the quadratic equation \(x^2 - 8x - 20 = 0\), we need to find two numbers that multiply to \(-20\) (the constant term) and add up to \(-8\) (the coefficient of the x term).

The pairs of numbers that multiply to \(-20\) are:

  • 1 and -20
  • 2 and -10
  • 4 and -5

Among these, we find that \(2\) and \(-10\) add up to \(-8\).

Thus, we can factor the quadratic as follows:

\[ x^2 - 8x - 20 = (x - 10)(x + 2) \]

Setting the factored expression to zero gives:

\((x - 10)(x + 2) = 0\)

So, the correct choice from the options provided is:

\((x - 10)(x + 2) = 0\)