Sonya planted a flower garden of tulips, daisies, and lilies. She planted 2 times as many tulips as daisies. She planted 3 times as many daisies as lilies. Sonya planted 42 tulips. How many flowers did she plant in all?

Question

(1 point)
Responses

48 flowers

48 flowers

56 flowers

56 flowers

63 flowers

63 flowers

70 flowers

Answer 1

Let's denote the number of lilies Sonya planted as \( L \), the number of daisies as \( D \), and the number of tulips as \( T \).

From the information given:

1. She planted 2 times as many tulips as daisies: \( T = 2D \)
2. She planted 3 times as many daisies as lilies: \( D = 3L \)
3. She planted 42 tulips: \( T = 42 \)

Now we can substitute \( T \) with 42 in the first equation:

\[ 42 = 2D \]

From this, we can solve for \( D \):

\[ D = \frac{42}{2} = 21 \]

Now substituting \( D = 21 \) into the second equation to find \( L \):

\[ 21 = 3L \]

Solving for \( L \):

\[ L = \frac{21}{3} = 7 \]

Now we have:

• \( T = 42 \) (tulips)
• \( D = 21 \) (daisies)
• \( L = 7 \) (lilies)

Now, let's find the total number of flowers she planted:

\[ T + D + L = 42 + 21 + 7 = 70 \]

Thus, the total number of flowers she planted is 70 flowers.