Sonia

Number of Problems Minutes of Writing
6 120
18 360
25 500
60 1,200

Maryna
Number of Problems Minutes of Writing
8 200
15 375
20 500
50 1,250
Based on the tables showing the number of minutes two writers spent writing math problems for two different lessons, who spent more time writing per problem? Write the answer in unit rate form.

(1 point)
Responses

Sonia spent the same amount of time as Maryna time writing per problem at the unit rate of 25 min.1 problem
.
Sonia spent the same amount of time as Maryna time writing per problem at the unit rate of 25 min.1 problem
.

Maryna spent less time writing per problem at the unit rate of 1 min.25 problems
.
Maryna spent less time writing per problem at the unit rate of 1 min.25 problems
.

Maryna spent more time writing per problem at the the unite rate of 25min.1 problem
.
Maryna spent more time writing per problem at the the unite rate of 25min.1 problem
.

Sonia spent more time writing per problem at the unit rate of 20 min. 1 problem
.
Sonia spent more time writing per problem at the unit rate of 20 min. 1 problem
.
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1 answer

To determine who spent more time writing per problem, we need to calculate the unit rate (minutes per problem) for both Sonia and Maryna.

For Sonia:

  1. 6 problems: 120 minutes → \( \frac{120 \text{ minutes}}{6 \text{ problems}} = 20 \text{ min/problem} \)
  2. 18 problems: 360 minutes → \( \frac{360 \text{ minutes}}{18 \text{ problems}} = 20 \text{ min/problem} \)
  3. 25 problems: 500 minutes → \( \frac{500 \text{ minutes}}{25 \text{ problems}} = 20 \text{ min/problem} \)
  4. 60 problems: 1200 minutes → \( \frac{1200 \text{ minutes}}{60 \text{ problems}} = 20 \text{ min/problem} \)

Average for Sonia: 20 min/problem

For Maryna:

  1. 8 problems: 200 minutes → \( \frac{200 \text{ minutes}}{8 \text{ problems}} = 25 \text{ min/problem} \)
  2. 15 problems: 375 minutes → \( \frac{375 \text{ minutes}}{15 \text{ problems}} = 25 \text{ min/problem} \)
  3. 20 problems: 500 minutes → \( \frac{500 \text{ minutes}}{20 \text{ problems}} = 25 \text{ min/problem} \)
  4. 50 problems: 1250 minutes → \( \frac{1250 \text{ minutes}}{50 \text{ problems}} = 25 \text{ min/problem} \)

Average for Maryna: 25 min/problem

Comparison:

  • Sonia spent 20 minutes per problem.
  • Maryna spent 25 minutes per problem.

Thus, Maryna spent more time writing per problem at the unit rate of 25 min/problem.

The correct response is:

Maryna spent more time writing per problem at the unit rate of 25 min/problem.

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