To calculate the volume of the product formed when 50 cm cubic of nitrogen dioxide is completely burnt in oxygen, we first need to determine the balanced chemical equation for the reaction.
The chemical equation for the combustion of nitrogen dioxide (NO2) in oxygen (O2) is:
2 NO2 + O2 → 2 NO3
From the balanced chemical equation, we can see that 2 moles of nitrogen dioxide react with 1 mole of oxygen to form 2 moles of nitrogen trioxide.
Now, let's calculate the volume of the product formed. Since the volumes are all measured at the same temperature and pressure, we can use the ideal gas law formula:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Rearranging the formula to solve for volume, we get:
V = nRT / P
Given that 1 mole of any gas occupies 22.4 liters at STP (standard temperature and pressure), we can calculate the volume of the product formed.
50 cm cubic of nitrogen dioxide is equal to 50/1000 = 0.05 liters.
Using the stoichiometry of the chemical equation, 2 moles of nitrogen dioxide will produce 2 moles of nitrogen trioxide.
Therefore, 0.05 liters of nitrogen dioxide will produce 2 x 0.05 = 0.1 moles of nitrogen trioxide.
Now, substituting the values into the formula:
V = (0.1 moles x 0.0821 L atm/mol K x 273 K) / 1 atm
V = 2.25 L
Therefore, the volume of the product formed when 50 cm cubic of nitrogen dioxide is completely burnt in oxygen is 2.25 liters.
Someone 50 cm cubic of nitrogen 2 oxide was completely burnt in oxygen what is the volume of the product formed all volumes measured at the same temperature and pressure
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