some turkeys take a lot of pride in being thanksgiving turkeys. In Turkey good taste(T) and fat bodies(B) are favorable to gross tasting skinny bodies. what is the probability that two turkeys (BbTT) and (Bbtt) will have fat good tasting offspring?

Answer 1

To analyze the genetics of the two turkeys (BbTT and Bbtt) and determine the probability of producing fat, good-tasting offspring, we need to specify the alleles involved in the traits for taste and body type.

Let's denote:

• B = allele for fat body
• b = allele for skinny body
• T = allele for good taste
• t = allele for gross taste

From the given turkey genotypes:

1. BbTT can produce gametes: BT, BT (there is no b or t since it's homozygous TT).
2. Bbtt can produce gametes: Bt and bt.

Next, we can set up a Punnett square to see the possible combinations of the offspring:

| | Bt | bt | |-----|------|------| | BT | BbTt | Bbtt | | BT | BbTt | Bbtt |

Now we analyze the progeny:

1. BbTt: This offspring has:

   • Body type: Bb (fat)
   • Taste: Tt (good taste)
   • Therefore, this offspring is both fat and has good taste.

2. Bbtt: This offspring has:

   • Body type: Bb (fat)
   • Taste: tt (gross taste)
   • Therefore, this offspring is fat but not good tasting.

From the Punnett square, we can see:

• 2 combinations (BbTt) which are fat and good tasting.
• 2 combinations (Bbtt) which are fat but not good tasting.

Thus, the probabilities are:

• 50% of the offspring (2 out of 4) will be BbTt (fat and good tasting).
• 50% of the offspring (2 out of 4) will be Bbtt (fat but not good tasting).

Therefore, the probability that two turkeys (BbTT) and (Bbtt) will have fat, good-tasting offspring (BbTt) is 2 out of 4 or 50%.