W=F•d•cosθ,
cosθ =W/F•d =
5460/68•220=0.365,
θ =arccos 0.65=68.6º
The force is applied at 68.6º with
the displacement or
with 360 º -68.6 with the displacement
Some object moves 220.0 m at an angle of 42° north of west. During this motion, a 68.0 N force acts on the same object, doing +5460.0 J of work on the object. Assuming the force is applied horizontal to ground, what is this force’s orientation? Is there more than one possible answer? Explain.
1 answer
1 answer