Let's set up a system of equations to solve for the prices of student and adult tickets.
Let x be the cost of a student ticket and y be the cost of an adult ticket.
From Mrs. Simon's purchase:
25x + 28y = 1034
From Mrs. Lopez's purchase:
28x + 31y = 1148
Now we can solve this system of equations. Let's start by multiplying the first equation by 28 and the second equation by 25 to eliminate x when adding the equations:
(25*28)x + (28*28)y = 25*1034
(28*25)x + (31*25)y = 28*1148
Simplifying, we get:
700x + 784y = 25850
700x + 775y = 32144
Subtracting the first equation from the second, we get:
-9y = 6286
y = -698.44
Now we can substitute this value back into one of the original equations to solve for x. Let's use Mrs. Simon's purchase:
25x + 28*(-698.44) = 1034
25x - 19584.32 = 1034
25x = 21618.32
x = 864.73
Therefore, a student ticket costs $864.73 and an adult ticket costs $698.44.
Some History teachers at Milford High School are purchasing tickets for students and their adult chaperones to go on a field trip to a nearby museumFor her Mrs. Simon bought 25 student tickets and 28 adult tickets, which cost a total of $1,034 Lopez spent $ 1,148getting 28 student tickets and 31 adult ticketsWhat is the price for each type of ticket? A student ticket costs and an adult ticket costs $
1 answer
1 answer