There is more than one answer to this.
If there are two people, Bob would get every odd-numbered piece, and 13 in all. If there are 12 children, Bob will get the first, thirteenth and 25th. If there are 8 children, Bob will get the 1st, 9th, 17th and 25th. If there are 24 people, Bob will get the first and 25th piece. If he always gets the last piece, the possible numbers of children (counting Bob) is 2, 3, 4, 6, 8, 12 and 24 -- any number evenly divisible into 24.
Some children were seated around a large round table. They pass around a box of candy containing 25 pieces. Bob took the first piece. Each child takes a piece of candy as the box is passed around. Bob also gets the last piece, and he may have more than the first and last piece.
How many children could be seated around the table.
Now, I really don't get this...and I need some help to start....but I think there mightbe 18 children other than Bob....thats just a guess.
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