If each of n students gets r rupees,
nr/(n-10) = r+20
nr/(n+10) = r-4
Now just solve for r and n.
Some amount of money is distributed to a some students equally. If the number of student is decreased by 10 then they will get 20 rupees more. If student is increased by 10 then they will get 4 rupees less. Find the amount and number of student?
3 answers
How to solve two variable in one time please.. Help me
same as always:
clear the fractions to get
nr = (r+20)(n-10)
nr = (r-4)(n+10)
nr = nr + 20n - 10r - 200
nr = nr - 4n + 10r - 40
20n-10r = 200
4n-10r = -40
or,
2n-r = 20
2n-5r = -20
So, r = 2n-20
2n-5(2n-20) = -20
2n-10n+100 = -20
-8n = -120
n = 15
so, r = 10
15 students share 150 rupees.
clear the fractions to get
nr = (r+20)(n-10)
nr = (r-4)(n+10)
nr = nr + 20n - 10r - 200
nr = nr - 4n + 10r - 40
20n-10r = 200
4n-10r = -40
or,
2n-r = 20
2n-5r = -20
So, r = 2n-20
2n-5(2n-20) = -20
2n-10n+100 = -20
-8n = -120
n = 15
so, r = 10
15 students share 150 rupees.