Solving with Elimination Practice

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Question
Solve the system of equations.
3x+6y=21

–5x+2y=13
(1 point)
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Remaining Attempts : 3

1 answer

To solve the system of equations using the elimination method, we can start by rewriting the equations:

  1. \(3x + 6y = 21\) (Equation 1)
  2. \(-5x + 2y = 13\) (Equation 2)

First, we can simplify Equation 1. Dividing all terms by 3:

\[ x + 2y = 7 \quad \text{(Simplified Equation 1)} \]

Now we have:

  1. \(x + 2y = 7\)
  2. \(-5x + 2y = 13\)

Next, let's eliminate \(y\) by subtracting Equation 1 from Equation 2. We can rewrite Equation 1 and then subtract:

Subtract Equation 1 from Equation 2:

\[ (-5x + 2y) - (x + 2y) = 13 - 7 \]

This simplifies to:

\[ -5x - x + 2y - 2y = 6 \]

Combining like terms gives:

\[ -6x = 6 \]

Dividing by -6:

\[ x = -1 \]

Now that we have \(x\), we can substitute it back into one of the original equations to find \(y\). We can use the simplified Equation 1:

\[ x + 2y = 7 \]

Substituting \(x = -1\):

\[ -1 + 2y = 7 \]

Adding 1 to both sides:

\[ 2y = 8 \]

Dividing by 2:

\[ y = 4 \]

So, the solution to the system of equations is:

\[ (x, y) = (-1, 4) \]

Final answer:

\[ \boxed{(-1, 4)} \]