Solving the equation C = Ba ^ (t/D) - K for t using logarithms with base a gives you:

Question

A. D loga (C/B +K)
B. loga (D(C+K)/B)
C. 1/D loga (C/B) +K
D. (loga ((C+K)/B)) / D
E. D loga ((C+K)/B)

I was able to solve up to (t/D) lna = (C+K)/B

Answer 1

actually, since the base is a, not e,
t/D = log_a (C+K)/B
t = D log_a ((C+K)/B)
so, choice E

Answer 2

oobleck is right just did it on APEX Calculus

Answer 3

True Im on apex too thats correct