Let's define the variables:
Let L be the length of the rectangle.
Let W be the width of the rectangle.
We are told that "The length of a rectangle is equal to triple the width." This can be written as the equation:
L = 3W
We are also told that "the perimeter is 86 centimeters." The formula for the perimeter of a rectangle is:
2L + 2W = Perimeter
Substituting the value of L from the first equation, we have:
2(3W) + 2W = 86
Simplifying the equation, we have:
6W + 2W = 86
8W = 86
W = 10.75
Now, we can substitute the value of W into the first equation to find L:
L = 3(10.75)
L = 32.25
Therefore, the dimensions of the rectangle are:
Length = 32.25 centimeters
Width = 10.75 centimeters
The system of equations that can be used to find the dimensions of the rectangle if the perimeter is 86 centimeters is:
L = 3W
2L + 2W = 86
Solving systems of equations word problems worksheet For all problems, define variables, write the system of equations and solve for all variables.
-The length of a rectangle is equal to triple the width. Which system of equations can be used to find the dimensions of the rectangle if the perimeter is 86 centimeters?
1 answer
1 answer