Solving Real-World Problems Using Long Division

Question

A company has $9,976 to evenly distribute among its top 15 employees. How much money will each of these employees receive, to the nearest dollar?
15 → 20
20 x ______ = 10,000
20 × 400 =______

Answer 1

To solve the problem of distributing $9,976 among 15 employees using long division, we start by dividing the total amount by the number of employees.

1. Setup the division: \( 9,976 \div 15 \)

2. Perform the Division:

   • 15 goes into 99 (the first two digits of 9,976), 6 times, because \( 15 \times 6 = 90 \).
   • Subtract \( 90 \) from \( 99 \): \( 99 - 90 = 9 \).
   • Bring down the next digit (7) to get 97.
   • 15 goes into 97, 6 times again, because \( 15 \times 6 = 90 \).
   • Subtract \( 90 \) from \( 97 \): \( 97 - 90 = 7 \).
   • Bring down the last digit (6) to get 76.
   • 15 goes into 76, 5 times, because \( 15 \times 5 = 75 \).
   • Subtract \( 75 \) from \( 76 \): \( 76 - 75 = 1 \) (the remainder).

3. Result:

   • So, \( 9,976 \div 15 = 665 \) remainder \( 1 \).

This means each employee receives $665, and since there's a remainder of $1, the total distribution is as close to evenly distributed as possible.

Thus, each employee will receive $665.

Important Note:

The original part of your question mentioning numbers related to 20 and 10,000 seems to be unrelated. If you are looking for how many times 20 goes into a certain number, just let me know so we can work on that separately too!