x ^ 2 + 4 y ^ 2 = 16
- x ^ 2 + y ^ 2 = 4
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3 y ^ 2 = 12 Divide both sides by 3
y ^ 2 = 12 / 3 = 4
y = + OR - 2
For y = 2
x ^ 2 + 4 y ^ 2 = 16
x ^ 2 + 4 * 2 ^ 2 = 16
x ^ 2 + 4 * 4 = 16
x ^ 2 + 16 = 16 Subtract 16 to both sides
x ^ 2 = 0
x = 0
For y = - 2
x ^ 2 + 4 y ^ 2 = 16
x ^ 2 + 4 * (- 2 ^ 2 ) = 16
x ^ 2 + 4 * 4 = 16
x ^ 2 + 16 = 16 Subtract 16 to both sides
x ^ 2 = 0
x = 0
The solutions are :
x = 0 , y = 2
( 0 , 2 )
and
x = 0 , y = - 2
( 0 , - 2 )
Solving Quadratic System
x^2+4y^2=16
x^2+y^2=4
Please SHOW WORK I'm having trouble solve this...
1 answer